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2(3/5)a=6
We move all terms to the left:
2(3/5)a-(6)=0
Domain of the equation: 5)a!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
2(+3/5)a-6=0
We multiply parentheses
6a^2-6=0
a = 6; b = 0; c = -6;
Δ = b2-4ac
Δ = 02-4·6·(-6)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*6}=\frac{-12}{12} =-1 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*6}=\frac{12}{12} =1 $
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