2(3/5)w+2w=32(3/5)w+2w=32

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Solution for 2(3/5)w+2w=32(3/5)w+2w=32 equation: 



2(3/5)w+2w=32(3/5)w+2w=32

We move all terms to the left:

2(3/5)w+2w-(32(3/5)w+2w)=0



Domain of the equation: 5)w!=0

w!=0/1

w!=0

w∈R





Domain of the equation: 5)w+2w)!=0

w!=0/1

w!=0

w∈R



We add all the numbers together, and all the variables

2(+3/5)w+2w-(32(+3/5)w+2w)=0

We add all the numbers together, and all the variables

2w+2(+3/5)w-(32(+3/5)w+2w)=0

We multiply parentheses

6w^2+2w-(32(+3/5)w+2w)=0

We multiply all the terms by the denominator


6w^2*5)w+2w)+2w*5)w+2w)-(32(+3=0

Wy multiply elements

150w^4=0

We do not support ewpression: w^4

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