2(3/5c-2)+1/2c=4-4/5c

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Solution for 2(3/5c-2)+1/2c=4-4/5c equation: 



2(3/5c-2)+1/2c=4-4/5c

We move all terms to the left:

2(3/5c-2)+1/2c-(4-4/5c)=0



Domain of the equation: 5c-2)!=0

c∈R





Domain of the equation: 2c!=0

c!=0/2

c!=0

c∈R





Domain of the equation: 5c)!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

2(3/5c-2)+1/2c-(-4/5c+4)=0

We multiply parentheses

6c+1/2c-(-4/5c+4)-4=0

We get rid of parentheses

6c+1/2c+4/5c-4-4=0

We calculate fractions


6c+5c/10c^2+8c/10c^2-4-4=0

We add all the numbers together, and all the variables

6c+5c/10c^2+8c/10c^2-8=0

We multiply all the terms by the denominator


6c*10c^2+5c+8c-8*10c^2=0

We add all the numbers together, and all the variables

13c+6c*10c^2-8*10c^2=0

Wy multiply elements

60c^3-80c^2+13c=0

We do not support ecpression: c^3

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