2(34-3x)=3(3x+4)

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Solution for 2(34-3x)=3(3x+4) equation: 



2(34-3x)=3(3x+4)

We move all terms to the left:

2(34-3x)-(3(3x+4))=0

We add all the numbers together, and all the variables

2(-3x+34)-(3(3x+4))=0

We multiply parentheses

-6x-(3(3x+4))+68=0



We calculate terms in parentheses: -(3(3x+4)), so:

3(3x+4)

We multiply parentheses

9x+12

Back to the equation:

-(9x+12)



We get rid of parentheses

-6x-9x-12+68=0

We add all the numbers together, and all the variables

-15x+56=0

We move all terms containing x to the left, all other terms to the right

-15x=-56

x=-56/-15

x=3+11/15

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