2(34z+2)=2(18z-12)

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Solution for 2(34z+2)=2(18z-12) equation: 



2(34z+2)=2(18z-12)

We move all terms to the left:

2(34z+2)-(2(18z-12))=0

We multiply parentheses

68z-(2(18z-12))+4=0



We calculate terms in parentheses: -(2(18z-12)), so:

2(18z-12)

We multiply parentheses

36z-24

Back to the equation:

-(36z-24)



We get rid of parentheses

68z-36z+24+4=0

We add all the numbers together, and all the variables

32z+28=0

We move all terms containing z to the left, all other terms to the right

32z=-28

z=-28/32

z=-7/8

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