2(3a+11)=4a+28

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Solution for 2(3a+11)=4a+28 equation: 



2(3a+11)=4a+28

We move all terms to the left:

2(3a+11)-(4a+28)=0

We multiply parentheses

6a-(4a+28)+22=0

We get rid of parentheses

6a-4a-28+22=0

We add all the numbers together, and all the variables

2a-6=0

We move all terms containing a to the left, all other terms to the right

2a=6

a=6/2

a=3

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