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2(3a+4)+2a=4(2a+2)+-3
We move all terms to the left:
2(3a+4)+2a-(4(2a+2)+-3)=0
We add all the numbers together, and all the variables
2a+2(3a+4)-(4(2a+2)+-3)=0
We use the square of the difference formula
2a+2(3a+4)-(4(2a+2)-3)=0
We multiply parentheses
2a+6a-(4(2a+2)-3)+8=0
We calculate terms in parentheses: -(4(2a+2)-3), so:We add all the numbers together, and all the variables
4(2a+2)-3
We multiply parentheses
8a+8-3
We add all the numbers together, and all the variables
8a+5
Back to the equation:
-(8a+5)
8a-(8a+5)+8=0
We get rid of parentheses
8a-8a-5+8=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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