2(3a+4)=5(a+1)=35

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Solution for 2(3a+4)=5(a+1)=35 equation: 



2(3a+4)=5(a+1)=35

We move all terms to the left:

2(3a+4)-(5(a+1))=0

We multiply parentheses

6a-(5(a+1))+8=0



We calculate terms in parentheses: -(5(a+1)), so:

5(a+1)

We multiply parentheses

5a+5

Back to the equation:

-(5a+5)



We get rid of parentheses

6a-5a-5+8=0

We add all the numbers together, and all the variables

a+3=0

We move all terms containing a to the left, all other terms to the right

a=-3

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