2(3a-20)+2(4a+10)=2(3a+30)+6a

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Solution for 2(3a-20)+2(4a+10)=2(3a+30)+6a equation: 



2(3a-20)+2(4a+10)=2(3a+30)+6a

We move all terms to the left:

2(3a-20)+2(4a+10)-(2(3a+30)+6a)=0

We multiply parentheses

6a+8a-(2(3a+30)+6a)-40+20=0



We calculate terms in parentheses: -(2(3a+30)+6a), so:

2(3a+30)+6a

We add all the numbers together, and all the variables

6a+2(3a+30)

We multiply parentheses

6a+6a+60

We add all the numbers together, and all the variables

12a+60

Back to the equation:

-(12a+60)



We add all the numbers together, and all the variables

14a-(12a+60)-20=0

We get rid of parentheses

14a-12a-60-20=0

We add all the numbers together, and all the variables

2a-80=0

We move all terms containing a to the left, all other terms to the right

2a=80

a=80/2

a=40

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