2(3a-4)+a+3=3(4a-5)

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Solution for 2(3a-4)+a+3=3(4a-5) equation: 



2(3a-4)+a+3=3(4a-5)

We move all terms to the left:

2(3a-4)+a+3-(3(4a-5))=0

We add all the numbers together, and all the variables

a+2(3a-4)-(3(4a-5))+3=0

We multiply parentheses

a+6a-(3(4a-5))-8+3=0



We calculate terms in parentheses: -(3(4a-5)), so:

3(4a-5)

We multiply parentheses

12a-15

Back to the equation:

-(12a-15)



We add all the numbers together, and all the variables

7a-(12a-15)-5=0

We get rid of parentheses

7a-12a+15-5=0

We add all the numbers together, and all the variables

-5a+10=0

We move all terms containing a to the left, all other terms to the right

-5a=-10

a=-10/-5

a=+2

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