2(3b+1)=-2b+26

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Solution for 2(3b+1)=-2b+26 equation: 



2(3b+1)=-2b+26

We move all terms to the left:

2(3b+1)-(-2b+26)=0

We multiply parentheses

6b-(-2b+26)+2=0

We get rid of parentheses

6b+2b-26+2=0

We add all the numbers together, and all the variables

8b-24=0

We move all terms containing b to the left, all other terms to the right

8b=24

b=24/8

b=3

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