2(3b+1)=-2b+26

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Solution for 2(3b+1)=-2b+26 equation:



2(3b+1)=-2b+26
We move all terms to the left:
2(3b+1)-(-2b+26)=0
We multiply parentheses
6b-(-2b+26)+2=0
We get rid of parentheses
6b+2b-26+2=0
We add all the numbers together, and all the variables
8b-24=0
We move all terms containing b to the left, all other terms to the right
8b=24
b=24/8
b=3

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