2(3b+1)=16

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Solution for 2(3b+1)=16 equation: 



2(3b+1)=16

We move all terms to the left:

2(3b+1)-(16)=0

We multiply parentheses

6b+2-16=0

We add all the numbers together, and all the variables

6b-14=0

We move all terms containing b to the left, all other terms to the right

6b=14

b=14/6

b=2+1/3

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