2(3b+2)=76

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Solution for 2(3b+2)=76 equation: 



2(3b+2)=76

We move all terms to the left:

2(3b+2)-(76)=0

We multiply parentheses

6b+4-76=0

We add all the numbers together, and all the variables

6b-72=0

We move all terms containing b to the left, all other terms to the right

6b=72

b=72/6

b=12

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