2(3b+4)=3(b-4)

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Solution for 2(3b+4)=3(b-4) equation: 



2(3b+4)=3(b-4)

We move all terms to the left:

2(3b+4)-(3(b-4))=0

We multiply parentheses

6b-(3(b-4))+8=0



We calculate terms in parentheses: -(3(b-4)), so:

3(b-4)

We multiply parentheses

3b-12

Back to the equation:

-(3b-12)



We get rid of parentheses

6b-3b+12+8=0

We add all the numbers together, and all the variables

3b+20=0

We move all terms containing b to the left, all other terms to the right

3b=-20

b=-20/3

b=-6+2/3

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