2(3b+5)=b-9

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Solution for 2(3b+5)=b-9 equation: 



2(3b+5)=b-9

We move all terms to the left:

2(3b+5)-(b-9)=0

We multiply parentheses

6b-(b-9)+10=0

We get rid of parentheses

6b-b+9+10=0

We add all the numbers together, and all the variables

5b+19=0

We move all terms containing b to the left, all other terms to the right

5b=-19

b=-19/5

b=-3+4/5

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