2(3b+9)=3(27+b)

Solution for 2(3b+9)=3(27+b) equation:

2(3b+9)=3(27+b)

We move all terms to the left:

2(3b+9)-(3(27+b))=0

We add all the numbers together, and all the variables

2(3b+9)-(3(b+27))=0

We multiply parentheses

6b-(3(b+27))+18=0


We calculate terms in parentheses: -(3(b+27)), so:

3(b+27)

We multiply parentheses

3b+81

Back to the equation:

-(3b+81)


We get rid of parentheses

6b-3b-81+18=0

We add all the numbers together, and all the variables

3b-63=0

We move all terms containing b to the left, all other terms to the right

3b=63

b=63/3

b=21