2(3b-1)+4b=10(6-3b)+38b

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Solution for 2(3b-1)+4b=10(6-3b)+38b equation: 



2(3b-1)+4b=10(6-3b)+38b

We move all terms to the left:

2(3b-1)+4b-(10(6-3b)+38b)=0

We add all the numbers together, and all the variables

2(3b-1)+4b-(10(-3b+6)+38b)=0

We add all the numbers together, and all the variables

4b+2(3b-1)-(10(-3b+6)+38b)=0

We multiply parentheses

4b+6b-(10(-3b+6)+38b)-2=0



We calculate terms in parentheses: -(10(-3b+6)+38b), so:

10(-3b+6)+38b

We add all the numbers together, and all the variables

38b+10(-3b+6)

We multiply parentheses

38b-30b+60

We add all the numbers together, and all the variables

8b+60

Back to the equation:

-(8b+60)



We add all the numbers together, and all the variables

10b-(8b+60)-2=0

We get rid of parentheses

10b-8b-60-2=0

We add all the numbers together, and all the variables

2b-62=0

We move all terms containing b to the left, all other terms to the right

2b=62

b=62/2

b=31

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