2(3b-1)+4b=10(6-3b)+38b

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Solution for 2(3b-1)+4b=10(6-3b)+38b equation:



2(3b-1)+4b=10(6-3b)+38b
We move all terms to the left:
2(3b-1)+4b-(10(6-3b)+38b)=0
We add all the numbers together, and all the variables
2(3b-1)+4b-(10(-3b+6)+38b)=0
We add all the numbers together, and all the variables
4b+2(3b-1)-(10(-3b+6)+38b)=0
We multiply parentheses
4b+6b-(10(-3b+6)+38b)-2=0
We calculate terms in parentheses: -(10(-3b+6)+38b), so:
10(-3b+6)+38b
We add all the numbers together, and all the variables
38b+10(-3b+6)
We multiply parentheses
38b-30b+60
We add all the numbers together, and all the variables
8b+60
Back to the equation:
-(8b+60)
We add all the numbers together, and all the variables
10b-(8b+60)-2=0
We get rid of parentheses
10b-8b-60-2=0
We add all the numbers together, and all the variables
2b-62=0
We move all terms containing b to the left, all other terms to the right
2b=62
b=62/2
b=31

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