2(3b-10)=b=50

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Solution for 2(3b-10)=b=50 equation: 



2(3b-10)=b=50

We move all terms to the left:

2(3b-10)-(b)=0

We add all the numbers together, and all the variables

-1b+2(3b-10)=0

We multiply parentheses

-1b+6b-20=0

We add all the numbers together, and all the variables

5b-20=0

We move all terms containing b to the left, all other terms to the right

5b=20

b=20/5

b=4

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