2(3b-3)=4(4b-3)

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Solution for 2(3b-3)=4(4b-3) equation: 



2(3b-3)=4(4b-3)

We move all terms to the left:

2(3b-3)-(4(4b-3))=0

We multiply parentheses

6b-(4(4b-3))-6=0



We calculate terms in parentheses: -(4(4b-3)), so:

4(4b-3)

We multiply parentheses

16b-12

Back to the equation:

-(16b-12)



We get rid of parentheses

6b-16b+12-6=0

We add all the numbers together, and all the variables

-10b+6=0

We move all terms containing b to the left, all other terms to the right

-10b=-6

b=-6/-10

b=3/5

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