2(3b-4)+11b=-7(b+8)

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Solution for 2(3b-4)+11b=-7(b+8) equation: 



2(3b-4)+11b=-7(b+8)

We move all terms to the left:

2(3b-4)+11b-(-7(b+8))=0

We add all the numbers together, and all the variables

11b+2(3b-4)-(-7(b+8))=0

We multiply parentheses

11b+6b-(-7(b+8))-8=0



We calculate terms in parentheses: -(-7(b+8)), so:

-7(b+8)

We multiply parentheses

-7b-56

Back to the equation:

-(-7b-56)



We add all the numbers together, and all the variables

17b-(-7b-56)-8=0

We get rid of parentheses

17b+7b+56-8=0

We add all the numbers together, and all the variables

24b+48=0

We move all terms containing b to the left, all other terms to the right

24b=-48

b=-48/24

b=-2

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