2(3b-4)=3(b+1)-5

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Solution for 2(3b-4)=3(b+1)-5 equation:


Simplifying
2(3b + -4) = 3(b + 1) + -5

Reorder the terms:
2(-4 + 3b) = 3(b + 1) + -5
(-4 * 2 + 3b * 2) = 3(b + 1) + -5
(-8 + 6b) = 3(b + 1) + -5

Reorder the terms:
-8 + 6b = 3(1 + b) + -5
-8 + 6b = (1 * 3 + b * 3) + -5
-8 + 6b = (3 + 3b) + -5

Reorder the terms:
-8 + 6b = 3 + -5 + 3b

Combine like terms: 3 + -5 = -2
-8 + 6b = -2 + 3b

Solving
-8 + 6b = -2 + 3b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3b' to each side of the equation.
-8 + 6b + -3b = -2 + 3b + -3b

Combine like terms: 6b + -3b = 3b
-8 + 3b = -2 + 3b + -3b

Combine like terms: 3b + -3b = 0
-8 + 3b = -2 + 0
-8 + 3b = -2

Add '8' to each side of the equation.
-8 + 8 + 3b = -2 + 8

Combine like terms: -8 + 8 = 0
0 + 3b = -2 + 8
3b = -2 + 8

Combine like terms: -2 + 8 = 6
3b = 6

Divide each side by '3'.
b = 2

Simplifying
b = 2

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