2(3b-4)=4(b+1)+2b

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Solution for 2(3b-4)=4(b+1)+2b equation:


Simplifying
2(3b + -4) = 4(b + 1) + 2b

Reorder the terms:
2(-4 + 3b) = 4(b + 1) + 2b
(-4 * 2 + 3b * 2) = 4(b + 1) + 2b
(-8 + 6b) = 4(b + 1) + 2b

Reorder the terms:
-8 + 6b = 4(1 + b) + 2b
-8 + 6b = (1 * 4 + b * 4) + 2b
-8 + 6b = (4 + 4b) + 2b

Combine like terms: 4b + 2b = 6b
-8 + 6b = 4 + 6b

Add '-6b' to each side of the equation.
-8 + 6b + -6b = 4 + 6b + -6b

Combine like terms: 6b + -6b = 0
-8 + 0 = 4 + 6b + -6b
-8 = 4 + 6b + -6b

Combine like terms: 6b + -6b = 0
-8 = 4 + 0
-8 = 4

Solving
-8 = 4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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