2(3b-4)=5(b-2)

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Solution for 2(3b-4)=5(b-2) equation:



2(3b-4)=5(b-2)
We move all terms to the left:
2(3b-4)-(5(b-2))=0
We multiply parentheses
6b-(5(b-2))-8=0
We calculate terms in parentheses: -(5(b-2)), so:
5(b-2)
We multiply parentheses
5b-10
Back to the equation:
-(5b-10)
We get rid of parentheses
6b-5b+10-8=0
We add all the numbers together, and all the variables
b+2=0
We move all terms containing b to the left, all other terms to the right
b=-2

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