2(3b-5)=4(6b-)2

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Solution for 2(3b-5)=4(6b-)2 equation: 



2(3b-5)=4(6b-)2

We move all terms to the left:

2(3b-5)-(4(6b-)2)=0

We add all the numbers together, and all the variables

2(3b-5)-(4(+6b)2)=0

We multiply parentheses

6b-(4(+6b)2)-10=0



We calculate terms in parentheses: -(4(+6b)2), so:

4(+6b)2

We multiply parentheses

48b

Back to the equation:

-(48b)



We add all the numbers together, and all the variables

-42b-10=0

We move all terms containing b to the left, all other terms to the right

-42b=10

b=10/-42

b=-5/21

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