2(3b-6)-(1-2b)=3-8(b-2)

Solution for 2(3b-6)-(1-2b)=3-8(b-2) equation:

2(3b-6)-(1-2b)=3-8(b-2)

We move all terms to the left:

2(3b-6)-(1-2b)-(3-8(b-2))=0

We add all the numbers together, and all the variables

2(3b-6)-(-2b+1)-(3-8(b-2))=0

We multiply parentheses

6b-(-2b+1)-(3-8(b-2))-12=0

We get rid of parentheses

6b+2b-(3-8(b-2))-1-12=0


We calculate terms in parentheses: -(3-8(b-2)), so:

3-8(b-2)

determiningTheFunctionDomain
-8(b-2)+3

We multiply parentheses

-8b+16+3

We add all the numbers together, and all the variables

-8b+19

Back to the equation:

-(-8b+19)


We add all the numbers together, and all the variables

8b-(-8b+19)-13=0

We get rid of parentheses

8b+8b-19-13=0

We add all the numbers together, and all the variables

16b-32=0

We move all terms containing b to the left, all other terms to the right

16b=32

b=32/16

b=2