2(3b=1)=-2b+26

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Solution for 2(3b=1)=-2b+26 equation: 



2(3b=1)=-2b+26

We move all terms to the left:

2(3b-(1))=0

We multiply parentheses

6b-2=0

We move all terms containing b to the left, all other terms to the right

6b=2

b=2/6

b=1/3

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