2(3c+1)=2(c+5)+4

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Solution for 2(3c+1)=2(c+5)+4 equation: 



2(3c+1)=2(c+5)+4

We move all terms to the left:

2(3c+1)-(2(c+5)+4)=0

We multiply parentheses

6c-(2(c+5)+4)+2=0



We calculate terms in parentheses: -(2(c+5)+4), so:

2(c+5)+4

We multiply parentheses

2c+10+4

We add all the numbers together, and all the variables

2c+14

Back to the equation:

-(2c+14)



We get rid of parentheses

6c-2c-14+2=0

We add all the numbers together, and all the variables

4c-12=0

We move all terms containing c to the left, all other terms to the right

4c=12

c=12/4

c=3

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