2(3c+1)=40

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Solution for 2(3c+1)=40 equation: 



2(3c+1)=40

We move all terms to the left:

2(3c+1)-(40)=0

We multiply parentheses

6c+2-40=0

We add all the numbers together, and all the variables

6c-38=0

We move all terms containing c to the left, all other terms to the right

6c=38

c=38/6

c=6+1/3

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