2(3c+9)=3(2c+6)

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Solution for 2(3c+9)=3(2c+6) equation:


Simplifying
2(3c + 9) = 3(2c + 6)

Reorder the terms:
2(9 + 3c) = 3(2c + 6)
(9 * 2 + 3c * 2) = 3(2c + 6)
(18 + 6c) = 3(2c + 6)

Reorder the terms:
18 + 6c = 3(6 + 2c)
18 + 6c = (6 * 3 + 2c * 3)
18 + 6c = (18 + 6c)

Add '-18' to each side of the equation.
18 + -18 + 6c = 18 + -18 + 6c

Combine like terms: 18 + -18 = 0
0 + 6c = 18 + -18 + 6c
6c = 18 + -18 + 6c

Combine like terms: 18 + -18 = 0
6c = 0 + 6c
6c = 6c

Add '-6c' to each side of the equation.
6c + -6c = 6c + -6c

Combine like terms: 6c + -6c = 0
0 = 6c + -6c

Combine like terms: 6c + -6c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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