2(3c-12)=6

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Solution for 2(3c-12)=6 equation: 



2(3c-12)=6

We move all terms to the left:

2(3c-12)-(6)=0

We multiply parentheses

6c-24-6=0

We add all the numbers together, and all the variables

6c-30=0

We move all terms containing c to the left, all other terms to the right

6c=30

c=30/6

c=5

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