2(3c-13)+2(4c+8)=64

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Solution for 2(3c-13)+2(4c+8)=64 equation: 



2(3c-13)+2(4c+8)=64

We move all terms to the left:

2(3c-13)+2(4c+8)-(64)=0

We multiply parentheses

6c+8c-26+16-64=0

We add all the numbers together, and all the variables

14c-74=0

We move all terms containing c to the left, all other terms to the right

14c=74

c=74/14

c=5+2/7

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