2(3c-2u)=4(1c+2u)

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Solution for 2(3c-2u)=4(1c+2u) equation:


Simplifying
2(3c + -2u) = 4(1c + 2u)
(3c * 2 + -2u * 2) = 4(1c + 2u)
(6c + -4u) = 4(1c + 2u)
6c + -4u = (1c * 4 + 2u * 4)
6c + -4u = (4c + 8u)

Solving
6c + -4u = 4c + 8u

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
6c + -4c + -4u = 4c + -4c + 8u

Combine like terms: 6c + -4c = 2c
2c + -4u = 4c + -4c + 8u

Combine like terms: 4c + -4c = 0
2c + -4u = 0 + 8u
2c + -4u = 8u

Add '4u' to each side of the equation.
2c + -4u + 4u = 8u + 4u

Combine like terms: -4u + 4u = 0
2c + 0 = 8u + 4u
2c = 8u + 4u

Combine like terms: 8u + 4u = 12u
2c = 12u

Divide each side by '2'.
c = 6u

Simplifying
c = 6u

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