2(3c-3)=12(c-2)

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Solution for 2(3c-3)=12(c-2) equation: 



2(3c-3)=12(c-2)

We move all terms to the left:

2(3c-3)-(12(c-2))=0

We multiply parentheses

6c-(12(c-2))-6=0



We calculate terms in parentheses: -(12(c-2)), so:

12(c-2)

We multiply parentheses

12c-24

Back to the equation:

-(12c-24)



We get rid of parentheses

6c-12c+24-6=0

We add all the numbers together, and all the variables

-6c+18=0

We move all terms containing c to the left, all other terms to the right

-6c=-18

c=-18/-6

c=+3

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