2(3c-4)-5(2c+1)=4(2c*6)-1

Solution for 2(3c-4)-5(2c+1)=4(2c*6)-1 equation:

2(3c-4)-5(2c+1)=4(2c*6)-1

We move all terms to the left:

2(3c-4)-5(2c+1)-(4(2c*6)-1)=0

We add all the numbers together, and all the variables

2(3c-4)-5(2c+1)-(4(+2c*6)-1)=0

We multiply parentheses

6c-10c-(4(+2c*6)-1)-8-5=0


We calculate terms in parentheses: -(4(+2c*6)-1), so:

4(+2c*6)-1

We multiply parentheses

48c-1

Back to the equation:

-(48c-1)


We add all the numbers together, and all the variables

-4c-(48c-1)-13=0

We get rid of parentheses

-4c-48c+1-13=0

We add all the numbers together, and all the variables

-52c-12=0

We move all terms containing c to the left, all other terms to the right

-52c=12

c=12/-52

c=-3/13