2(3c-5)=3c+17

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Solution for 2(3c-5)=3c+17 equation: 



2(3c-5)=3c+17

We move all terms to the left:

2(3c-5)-(3c+17)=0

We multiply parentheses

6c-(3c+17)-10=0

We get rid of parentheses

6c-3c-17-10=0

We add all the numbers together, and all the variables

3c-27=0

We move all terms containing c to the left, all other terms to the right

3c=27

c=27/3

c=9

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