2(3d+1)=3(d-2)

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Solution for 2(3d+1)=3(d-2) equation: 



2(3d+1)=3(d-2)

We move all terms to the left:

2(3d+1)-(3(d-2))=0

We multiply parentheses

6d-(3(d-2))+2=0



We calculate terms in parentheses: -(3(d-2)), so:

3(d-2)

We multiply parentheses

3d-6

Back to the equation:

-(3d-6)



We get rid of parentheses

6d-3d+6+2=0

We add all the numbers together, and all the variables

3d+8=0

We move all terms containing d to the left, all other terms to the right

3d=-8

d=-8/3

d=-2+2/3

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