2(3d+3)=d-19

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Solution for 2(3d+3)=d-19 equation: 



2(3d+3)=d-19

We move all terms to the left:

2(3d+3)-(d-19)=0

We multiply parentheses

6d-(d-19)+6=0

We get rid of parentheses

6d-d+19+6=0

We add all the numbers together, and all the variables

5d+25=0

We move all terms containing d to the left, all other terms to the right

5d=-25

d=-25/5

d=-5

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