2(3d+4)+1=3(d-1)-9

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Solution for 2(3d+4)+1=3(d-1)-9 equation: 



2(3d+4)+1=3(d-1)-9

We move all terms to the left:

2(3d+4)+1-(3(d-1)-9)=0

We multiply parentheses

6d-(3(d-1)-9)+8+1=0



We calculate terms in parentheses: -(3(d-1)-9), so:

3(d-1)-9

We multiply parentheses

3d-3-9

We add all the numbers together, and all the variables

3d-12

Back to the equation:

-(3d-12)



We add all the numbers together, and all the variables

6d-(3d-12)+9=0

We get rid of parentheses

6d-3d+12+9=0

We add all the numbers together, and all the variables

3d+21=0

We move all terms containing d to the left, all other terms to the right

3d=-21

d=-21/3

d=-7

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