2(3d+4)=20

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Solution for 2(3d+4)=20 equation: 



2(3d+4)=20

We move all terms to the left:

2(3d+4)-(20)=0

We multiply parentheses

6d+8-20=0

We add all the numbers together, and all the variables

6d-12=0

We move all terms containing d to the left, all other terms to the right

6d=12

d=12/6

d=2

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