2(3d+5)=5(d+1)

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Solution for 2(3d+5)=5(d+1) equation: 



2(3d+5)=5(d+1)

We move all terms to the left:

2(3d+5)-(5(d+1))=0

We multiply parentheses

6d-(5(d+1))+10=0



We calculate terms in parentheses: -(5(d+1)), so:

5(d+1)

We multiply parentheses

5d+5

Back to the equation:

-(5d+5)



We get rid of parentheses

6d-5d-5+10=0

We add all the numbers together, and all the variables

d+5=0

We move all terms containing d to the left, all other terms to the right

d=-5

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