2(3d-4)+2(d-6)-3(d-10)=10

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Solution for 2(3d-4)+2(d-6)-3(d-10)=10 equation: 



2(3d-4)+2(d-6)-3(d-10)=10

We move all terms to the left:

2(3d-4)+2(d-6)-3(d-10)-(10)=0

We multiply parentheses

6d+2d-3d-8-12+30-10=0

We add all the numbers together, and all the variables

5d=0

d=0/5

d=0

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