2(3d-5)-5(d+2)=4d+10

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Solution for 2(3d-5)-5(d+2)=4d+10 equation:


Simplifying
2(3d + -5) + -5(d + 2) = 4d + 10

Reorder the terms:
2(-5 + 3d) + -5(d + 2) = 4d + 10
(-5 * 2 + 3d * 2) + -5(d + 2) = 4d + 10
(-10 + 6d) + -5(d + 2) = 4d + 10

Reorder the terms:
-10 + 6d + -5(2 + d) = 4d + 10
-10 + 6d + (2 * -5 + d * -5) = 4d + 10
-10 + 6d + (-10 + -5d) = 4d + 10

Reorder the terms:
-10 + -10 + 6d + -5d = 4d + 10

Combine like terms: -10 + -10 = -20
-20 + 6d + -5d = 4d + 10

Combine like terms: 6d + -5d = 1d
-20 + 1d = 4d + 10

Reorder the terms:
-20 + 1d = 10 + 4d

Solving
-20 + 1d = 10 + 4d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-4d' to each side of the equation.
-20 + 1d + -4d = 10 + 4d + -4d

Combine like terms: 1d + -4d = -3d
-20 + -3d = 10 + 4d + -4d

Combine like terms: 4d + -4d = 0
-20 + -3d = 10 + 0
-20 + -3d = 10

Add '20' to each side of the equation.
-20 + 20 + -3d = 10 + 20

Combine like terms: -20 + 20 = 0
0 + -3d = 10 + 20
-3d = 10 + 20

Combine like terms: 10 + 20 = 30
-3d = 30

Divide each side by '-3'.
d = -10

Simplifying
d = -10

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