2(3d-5)=2d+6

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Solution for 2(3d-5)=2d+6 equation: 



2(3d-5)=2d+6

We move all terms to the left:

2(3d-5)-(2d+6)=0

We multiply parentheses

6d-(2d+6)-10=0

We get rid of parentheses

6d-2d-6-10=0

We add all the numbers together, and all the variables

4d-16=0

We move all terms containing d to the left, all other terms to the right

4d=16

d=16/4

d=4

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