2(3e-5)+1=2(e+4)-1

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Solution for 2(3e-5)+1=2(e+4)-1 equation: 



2(3e-5)+1=2(e+4)-1

We move all terms to the left:

2(3e-5)+1-(2(e+4)-1)=0

We multiply parentheses

6e-(2(e+4)-1)-10+1=0



We calculate terms in parentheses: -(2(e+4)-1), so:

2(e+4)-1

We multiply parentheses

2e+8-1

We add all the numbers together, and all the variables

2e+7

Back to the equation:

-(2e+7)



We add all the numbers together, and all the variables

6e-(2e+7)-9=0

We get rid of parentheses

6e-2e-7-9=0

We add all the numbers together, and all the variables

4e-16=0

We move all terms containing e to the left, all other terms to the right

4e=16

e=16/4

e=4

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