2(3f-1)+f=6-f

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Solution for 2(3f-1)+f=6-f equation:



2(3f-1)+f=6-f
We move all terms to the left:
2(3f-1)+f-(6-f)=0
We add all the numbers together, and all the variables
2(3f-1)+f-(-1f+6)=0
We add all the numbers together, and all the variables
f+2(3f-1)-(-1f+6)=0
We multiply parentheses
f+6f-(-1f+6)-2=0
We get rid of parentheses
f+6f+1f-6-2=0
We add all the numbers together, and all the variables
8f-8=0
We move all terms containing f to the left, all other terms to the right
8f=8
f=8/8
f=1

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