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2(3g+2)=(1/2)(12g
We move all terms to the left:
2(3g+2)-((1/2)(12g)=0
Domain of the equation: 2)12g!=0We add all the numbers together, and all the variables
g!=0/1
g!=0
g∈R
2(3g+2)-((+1/2)12g=0
We multiply parentheses
6g-((+1/2)12g+4=0
We multiply all the terms by the denominator
6g*2)12g+4-((+1=0
Wy multiply elements
12g^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$g=\frac{-b}{2a}=\frac{0}{24}=0$
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