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2(3g+2)=1/2(12g+5)
We move all terms to the left:
2(3g+2)-(1/2(12g+5))=0
Domain of the equation: 2(12g+5))!=0We multiply parentheses
g∈R
6g-(1/2(12g+5))+4=0
We multiply all the terms by the denominator
6g*2(12g+5))-(1+4*2(12g+5))=0
Wy multiply elements
12g^2(1+8g(1=0
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