2(3h+-1)+4h=10(2-3h)+38h

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Solution for 2(3h+-1)+4h=10(2-3h)+38h equation: 



2(3h+-1)+4h=10(2-3h)+38h

We move all terms to the left:

2(3h+-1)+4h-(10(2-3h)+38h)=0

We add all the numbers together, and all the variables

2(3h-1)+4h-(10(-3h+2)+38h)=0

We add all the numbers together, and all the variables

4h+2(3h-1)-(10(-3h+2)+38h)=0

We multiply parentheses

4h+6h-(10(-3h+2)+38h)-2=0



We calculate terms in parentheses: -(10(-3h+2)+38h), so:

10(-3h+2)+38h

We add all the numbers together, and all the variables

38h+10(-3h+2)

We multiply parentheses

38h-30h+20

We add all the numbers together, and all the variables

8h+20

Back to the equation:

-(8h+20)



We add all the numbers together, and all the variables

10h-(8h+20)-2=0

We get rid of parentheses

10h-8h-20-2=0

We add all the numbers together, and all the variables

2h-22=0

We move all terms containing h to the left, all other terms to the right

2h=22

h=22/2

h=11

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