2(3k+1)+2=28

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Solution for 2(3k+1)+2=28 equation: 



2(3k+1)+2=28

We move all terms to the left:

2(3k+1)+2-(28)=0

We add all the numbers together, and all the variables

2(3k+1)-26=0

We multiply parentheses

6k+2-26=0

We add all the numbers together, and all the variables

6k-24=0

We move all terms containing k to the left, all other terms to the right

6k=24

k=24/6

k=4

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