2(3k+1)=k+8

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Solution for 2(3k+1)=k+8 equation: 



2(3k+1)=k+8

We move all terms to the left:

2(3k+1)-(k+8)=0

We multiply parentheses

6k-(k+8)+2=0

We get rid of parentheses

6k-k-8+2=0

We add all the numbers together, and all the variables

5k-6=0

We move all terms containing k to the left, all other terms to the right

5k=6

k=6/5

k=1+1/5

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